Apr 17, 2020· The 78 kg student in the figure balances a 1000 kg elephant on a hydraulic lift. a) What is the diameter of the piston the student is standing on? I got 0.56 m b) When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 30 cm . What is the second student's mass?
Jan 29, 2016· A)What is the diameter of the piston the student is standing on? which I got to be .46m which is correct. B)When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40 cm . What is the second student's mass?
The student weighs 784 N (F grav = 80 kg * 9.8 m/s/s). To lift a 784-Newton person at constant speed, 784 N of force must be applied to it (Newton's laws). The force is up, the displacement is up, and so the angle theta in the work equation is 0 degrees. Thus, W = (784 N) * (8 m) * cos (0 degrees) = 6272 Joules
Nov 06, 2010· The 70kg student in the figure balances a 1200kg elephant on a hydraulic lift. A second 70kg student joins the first student. How high do they lift the elephant? diameter of the piston elephant is on = 2.0m diameter of the piston student is on = 0.48m The liquid inside the lift is oil, therefore rho = 900 kg/m3
Dec 03, 2015· What is the diameter of the piston the student is standing on? A: 0.5 m When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 30 cm . What is the second student's mass? I keep getting a big number.
Examples 1. What is the pressure head at the bottom of a 98 ft (30 m) water tower? ()()() 1000 kg/m 9.8 m/s 30 m32 Δpp p gh=−= at h atm ρ 2.9 10 Pa5 42 psig 56.7 psi absolute Gaugepressure vs
Resultant forces will cause acceleration, which can be described and calculated using Newton's laws of motion. Weight is caused by the gravitational effect of a planet attracting an object's mass.
Question: The 80 Kg Student In The Figure(Figure 1) Balances A 1000 Kg Elephant On A Hydraulic Lift. The Diameter Of The Piston The Student Is Standing On=0.57m When A Second Student Joins The First, The Height Difference Between The Liquid Levels In The Right And Left Pistons Is 30 Cm .
Dec 07, 2012· The 70kg student in the figure balances a 1200kg elephant on a hydraulic lift? A second 70kg student joins the first student. How high do they lift the elephant? Answer Save. 1 Answer. Relevance. Dr. Watkin,. I presume. Lv 7. 8 years ago. Favorite Answer. Need more info, like piston diameters.
Apr 20, 2016· How to calculate the force of gravitational attraction between a person (mass=75 kg) & Earth (mass 5.98x10^24 kg and mean radius 6.37x10^6m) ? Physics Circular Motion and Gravitation Newton's Law of Gravitation. 1 Answer Johnson Z. Apr 20, 2016 #740N# Explanation: The gravitational force can be calculated with the formula: ...
Please explain your reasoning. (1) Problem 5 (5 points): Physics at the Zoo: A 70 kg student in the figure below balances a 1200 kg elephant on a hydraulic lift. a) What is the diameter of the piston the student is standing on? (2) b) When a second student joins the first, the piston sinks 35 cm. What is the second student's mass? (3)
decay into a proton (mass 1:67 3110 27 kg) and an electron (mass 9:11 10 kg). The proton and electron were shot out back-to-back. The proton speed was measured to be 1:0 105 m{ s and the electron speed was 3:0 107 m{ s. No other decay products were detected. (a) Was momentum conserved in …
Jan 19, 2015· Hi, I need some help with this question: The 78kg student in the figure balances a 1100kg elephant on a hydraulic lift. a) What is the diameter of the piston the student is standing on? I got this, and its 0.53m b) When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40cm .
The 68kg student in the figure balances a 1100kg elephant on a hydraulic lift. The diameter of the piston the elephant is on is 2 m. And the diameter of the piston that the student stands on is 0.5 m. The fluid in inside is oil. When a second student joins the first, the piston sinks 40cm . What is the second student's mass?
The 73 kg student in the figure (Figure 1) balances a 1200 kg elephant on a hydraulic lift. Part A: What is the diameter of the piston the student is standing on? Express your answer to two significant figures and include the appropriate units. Answer is 0.49
Question: The 68 Kg Student In The Figure(Figure 1) Balances A 1000 Kg Elephant On A Hydraulic Lift. What Is The Diameter Of The Piston The Student Is Standing On? When A Second Student Joins The First, The Height Difference Between The Liquid Levels In The Right And Left Pistons Is 40 Cm .
The 80kg student balances a 1300kg elephant on a hydraulic lift. (U-Tube) ... (kg) it can lift if the diameter of the output line is 32.0 cm? physics. The small piston of a hydraulic lift has a diameter of 8 cm and its large piston has a diameter of 40cm. The lift raises a load of 15,000 Newtons.
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Oct 05, 2008· The 70kg student in the figure balances a 1200kg elephant on a hydraulic lift. A second 70kg student joins the first student. How high do they lift the elephant? diameter of the piston elephant is on = 2.0m diameter of the piston student is on = 0.48m The liquid inside the lift is oil, therefore rho = 900 kg/m 3
Question: The 73 Kg Student In The Figure(Figure 1) Balances A 1400 Kg Elephant On A Hydraulic Lift. When A Second Student Joins The First, The Height Difference Between The Liquid Levels In The Right And Left Pistons Is 35 Cm .
Nov 19, 2013· B) I think you need to know the density of oil for this. But if the students fall 40 cm, then the elephant rises 40cm * (0.49 / 2)² = 2.4 cm. so the difference is h = 42.4 cm. Then. M * g / (πd²/4) = ρgh. M = ρhπd²/4 = ρ * 0.424m * π * (0.49m)²/4 = ρ * 0.0811. where M is kg and ρ is in kg/m³. For instance, if ρ = 800 kg/m³, then ...
Question: The 80 Kg Student In The Figure(Figure 1) Balances A 1000 Kg Elephant On A Hydraulic Lift. What Is The Diameter Of The Piston The Student Is Standing On? Express Your Answer To Two Significant Figures And Include The Appropriate Units.
A 50.0 kg crate is lifted to a height of 2.0 meters in the same time as a 25.0 kg crate is lifted to a height of 4 meters. The rate at which energy is used (i.e., power) in raising the 50.0 kg crate is ____ as the rate at which energy is used to lift the 25.0 kg crate.
Calculate the unknown variable in the equation for gravitational potential energy, where potential energy is equal to mass multiplied by gravity and height; PE = mgh. Calculate for different gravity of different enviornments - Earth, the Moon, Jupiter, or specify your own. Free online physics calculators, mechanics, energy, calculators.
